Can someone help me out with coding strands of DNA??

Ok. I missed class last week due to personal reasons. Anyways, I missed the section on how to code strands of DNA. I go to OSU, so of course my professor wouldnt be able to help me since theres over 400 people in the class and I don't know anyone else taking this class.





Anyways, we got a worksheet to do with 3 questions. I read in my book on how to do this, but I don't understand it.





The questions we got were:





The following nucleotide sequence is the coding strand of DNA:


ATG ACT TGT GTC CTA TAG





Please provide the sequence of the template strand.





Please transcribe the mRNA from this DNA.





Please translate the amino acid sequence from this message.








Can anyone help me out? And perhaps, give me a short summary on how to do this?

Can someone help me out with coding strands of DNA??
WHY do people get these things mixed





Nucleic acid sequences are always written in the 5'-%26gt;3' direction





so you have the coding sequence:





5' -ATG ACT TGT GTC CTA TAG -3'





The template sequence you can find easily by pairing A with T, T with A, G with C and C with G





5' -ATG ACT TGT GTC CTA TAG -3'


3' -TAC TGA ACA CAG GAT ATC -5'





Now, for a not very advanced class the professor would be content with the answer TAC TGA ACA CAG GAT ATC as the template sequence. However that would be wrong, since nucleic acid sequences have to be written in the 5'-%26gt;3' direction so the truly correct answer is:


5'-CTA TAG GAC ACA AGT CAT-3'





mRNA has the same sequence as the coding DNA with only difference that you have U instead of T:


5' -AUG ACU UGU GUC CUA UAG -3'





You need a table with the code (every 3 bases make-up a codon that codes for a specific amino acid). You can also use on-line tools like: http://au.expasy.org/tools/dna.html...


M T C V L Stop or if you prefer 3-letter code





Met Thr Cys Val Leu stop (well stop is not part of the protein but its just to show that the last codon is a stop codon)
Reply:the mRNA will be UAC UGA ACA CAG GAU AUG


and the amino acids in order are:tyrosine,stop codon,threonin,glutamine,acid aspartic,start codon


and the template strand is TAC TGA ACA CAG GAT ATC
Reply:I could be wrong, but I think the amino acid sequence as translated from the mRNA would be:


(Start) Methionine, threonine, cysteine, valine, leucine, stop codon
Reply:There are 4 bases in DNA : A, T, C, G.


A always goes with T and C always goes with G


There are 4 bases in RNA: A, U, C, G


A always goes with U and C always goes with G





The question gives you a coding strand and from this a template strand must be made. With the above rules this means that the template strand must be:


TAC TGA ACA CAG GAT ATC





From the template strand a mRNA is transcribed and with the above rules the mRNA strand must be:


AUG ACU UGU GUC CUA UAG





From the mRNA strand a sequence of amino acids can be deciphered. Each 3 bases = 1 codon. each codon = 1 amino acid. You should have been given an amino acid/codon table or something. Use the mRNA strand to figure out the amino acid sequence.





Good luck!
Reply:TAC TGA ACA CAG GAT ATC - template strand


UAC UGA ACA CAG GAU AUC - mrna





i dont have the amino acid sequence chart with me at the moment..

wild flowers